(3x+1)^5/6=32

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Solution for (3x+1)^5/6=32 equation: 



(3x+1)^5/6=32

We move all terms to the left:

(3x+1)^5/6-(32)=0

We multiply all the terms by the denominator


(3x+1)^5-32*6=0

We add all the numbers together, and all the variables

(3x+1)^5-192=0

We move all terms containing x to the left, all other terms to the right

(3x+1)^5=192

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